The crystal structure of Bi2Pb2V2O10 has been determined by X-ray single crystal diffraction method. The crystal belongs to triclinic system with space group P1, Z=1 and cell parameters: α=7.084(4)? b=7.278(3) ?, c=5.587(3)?, α=111.91(5)° β=95.01(6)°γ=108.86(4)°ν=245.70 ?3, Dx,=7.35 g/cm, (MoKα)=678.94cm-1, F(000)= 456. The structure was analysed by means of Patterson function and Fourier techniques. The coordinates of atoms, isotropic and anisotropic thermal parameters were refined to R=0.079 for 1054 independent reflections by least-squares refinement procedure. The structure analysis shows that eight O atoms around Pb atom form a polyhedron with 8-vertexes and six O atoms around Bi atom form a polyhedron with 6-ver-texes. Two Pb-0 polyhedra with common edge connect with two Bi-0 polyhedra with common edge. They extend along be plane. The effect of absorption was discussed. Finally, the comparison of the structure of Bi2Pb2V2O10 with Pb2SO5 was made.